If its acceleration in the extreme position is 27 cm/s 2, find the period. Given: path length = 8 cm, amplitude = 8/2 = 4 cm, V maxĪ particle performs simple harmonic motion of amplitude 3 cm. If the length of its path is 8 cm, calculate its period. The maximum velocity of a particle performing simple harmonic motion is 6.28 cm/s. Given: Period = T = 6 s, V max = 6.28 cm/s, x = 3Ĭm, particle passes through mean position, α = 0.Īngular velocity = ω = 2π/T = 2π/6 = π/3 rad/sĭisplacement of a particle performing S.H.M. Find the time taken by it to describe a distance of 3 cm from its equilibrium position. A particle executing simple harmonic motion has a period of 6 s and its maximum velocity during oscillations is 6.28 cm/s.
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